If a stationary observer throws a rock out in the radial direction in a Schwarzschild geometry, what is the relationship between the energy of the rock and its speed in the observer's frame?(adsbygoogle = window.adsbygoogle || []).push({});

I'm a bit confused because the book seems to say it's [tex]E = \frac{m}{\sqrt{1-V^2}}[/tex], but I thought that only applied to inertial frames in special relativity.

Thanks.

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Formula for energy in GR

Loading...

Similar Threads - Formula energy | Date |
---|---|

I Energy-momentum formula and deBroglie wavelength | Jan 19, 2018 |

Problem about equality of energy formulas | Feb 9, 2016 |

Energy formulas in SR | Apr 24, 2015 |

The Energy-momentum formula considering internal energy | Mar 6, 2014 |

Inconsistency in formulas for relativistic energy | Nov 17, 2013 |

**Physics Forums - The Fusion of Science and Community**