Formula for pull force of a ring magnet on a metal rod

  • Thread starter kvkskumar
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Hi,
Can somebody give me the formula for pull force of ring magnet(permanent. not solenoid or electric) on a metal rod.

Also is the formula for pull force by a solenoid given below correct. If not let me know the correct one for the below.

Force = ((N x I)^2 x μ x A) / (2 x g^2)

N = the number of turns in the solenoid
I = the current, in amperes (A), running through the solenoid
A = the cross-sectional area, in meters-squared, of the solenoidal magnet
g = the distance, in meters, between the magnet and the piece of metal
μ = 4 x pi x 10^-7
^ = symbol that means "to the power of"
 

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