Is This the Best Formula for Calculating Work and Time?

In summary, the conversation discussed different formulas for calculating work and time, including the formula W = F s in physics, and the formula N1 * D1 * W1 = N2 * D2 * W2 for problems involving multiple workers and days. There was also discussion about the meaning of "rate of work per day per man" and how it relates to solving word problems involving work and time.
  • #1
momentum
111
0
Hi,

whats the formula for work and Time ?


is it this ?

N1 * D1 * W1 =N2*D2*W2

where ,
N1=No of Persons
D1=No of days
W1=work


N2=No of Persons
D2=No of days
W2=work


is that's formula correct for work and time ?
 
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  • #2
The simplest formula for mechanical work (in Physics) is
[tex] W = F s [/tex]
Here, the force is contant and parallel to displacement and the body moves in a steady direction. W is work, F is force and s is displacement. The result is in Joules.

Unless you want manhours? What exactly are you trying to do? :)
 
  • #3
no...there is no physics involved in it.

i'm talking about maths.

problems like..."20 man works for 10 days did a work, how long it would be taken by 30 man"?

this kind of problem

whats the formula ?

I have forgotten the formula...is it like same as i posted ?
 
  • #4
[tex]N_1 R D_1 = W = N_2 R D_2[/tex]

Where: N = number of men; R = rate of work done per man (assumed constant); D = days (or time); W = total work done.
 
  • #5
>R = rate of work done per man (assumed constant);

what does it mean ?

can you give an example of it ?

thank you
 
  • #6
Don't treat this as some esoteric formula from the ancients. It should be just "common sense", a variation of "Distance = Rate X time".

An example of R would be: a man can lift 50 bales of hay per day, so R = 50 bales/day/man.

So, if one man can lift 50 per day, how much total can be lifted in 3 days by 5 men?

Using W = N R D gives, W(total) = (5 men) (50 bales/day/man) (3 days) = 750 bales

But to solve a problem like " if 20 men working 10 days did a certain amount of work, how long would it take 30 men to do the same work?" you don't have to know R. Just use:

[tex]N_1 R D_1 = W = N_2 R D_2[/tex]
(20)(R)(10) = (30)(R)([itex]D_2[/itex])

Note that the Rs just drop out, and [itex]D_2[/itex] = 20/3 days.
 
  • #7
Those are the dumbest of word problems. I would be tempted to answer : "The job would never get done, because the extra men would entice the entire lot to unionise and strike for better pay and conditions".
 
  • #8
this is correct
N1 * D1 * W2 =N2*D2*W1
where ,
N1=No of Persons
D1=No of days
W1=work


N2=No of Persons
D2=No of days
W2=work
 
  • #9
Except that just "work" is meaningless. I prefer Doc Al's "rate of work per day per man".
 
  • #10
yes bro u r right for "work" explanation but except tht mine formula is best one
 

What is the formula for work?

The formula for work is W = F x d, where W is work, F is force, and d is displacement. This formula is used to calculate the amount of energy required to move an object.

What is the formula for time?

The formula for time is t = d/v, where t is time, d is distance, and v is velocity. This formula is used to calculate the amount of time it takes an object to travel a certain distance at a given velocity.

How are the formula for work and time related?

The formula for work and time are related through the concept of power, which is the rate at which work is done. The formula for power is P = W/t, where P is power, W is work, and t is time. This shows that the amount of work done is directly proportional to the amount of time it takes to do it.

What are some real-life applications of the formula for work and time?

The formula for work and time is used in various fields, such as physics, engineering, and construction. It is used to calculate the amount of energy required to lift objects, the speed at which vehicles can travel, and the efficiency of machines.

How can the formula for work and time be manipulated to solve different problems?

The formula for work and time can be manipulated by rearranging the variables to solve for different unknowns. For example, if the value of force is unknown, the formula can be rearranged to solve for it: F = W/d. This allows scientists to solve a variety of problems and make predictions about the amount of work and time needed for different tasks.

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