Found half an answer, I with the direction please.

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In summary, the initial velocity of the projectile is 22 m/s at an angle of 63 degrees above the horizontal.
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nesan
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Homework Statement



A projectile is launched with a horizontal velocity of 10 m/s and a vertical velocity of 20 m/s. What is the magnitude and direction of the projectile’s initial velocity?

The Attempt at a Solution

I've tried using the trigonometric method but I end up with only 1 side and 1 angle which isn't good. I could logically think that since one side is 20 and one side is 10, the angle would be

90 / 3 = 30

30 * 2 = 60

But the answer sheet says 63 degrees. :"(
I found the magnitude but the problem is I can't find the direction. More specifically, at what degree is it traveling at.

The magnitude is 22.

So it should be

22 m/s [Up x Horizontal]

x = an unknown angle

I'm having trouble finding the value of x.

Than you. :3

NVM GOT IT. LOL :D
 
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  • #2
nesan said:

Homework Statement



A projectile is launched with a horizontal velocity of 10 m/s and a vertical velocity of 20 m/s. What is the magnitude and direction of the projectile’s initial velocity?

The Attempt at a Solution




I've tried using the trigonometric method but I end up with only 1 side and 1 angle which isn't good. I could logically think that since one side is 20 and one side is 10, the angle would be

90 / 3 = 30

30 * 2 = 60

But the answer sheet says 63 degrees. :"(



I found the magnitude but the problem is I can't find the direction. More specifically, at what degree is it traveling at.

The magnitude is 22.

So it should be

22 m/s [Up x Horizontal]

x = an unknown angle

I'm having trouble finding the value of x.

Than you. :3

NVM GOT IT. LOL :D


Have you drawn a picture?
If you did you would see a right-angled triangle, and just use the Tangent function.
 

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