Four charges q1 = q3 = -q and q2 = q4 = +q, where q = 4 µC, are fixed at the corners of a square with sides a = 1.3 m.
q1 M' q4
(b) Find the force on a test charge Q = -0.3 µC placed at the midpoint M' of the top side of the square
Coulombs law: F = (k*q1*q2)/r^2
The Attempt at a Solution
Fq1M' = (k(4uC)(0.3uC))/(0.65^2) = 0.025533728
Fq4M' = 0.025533728
theta = tan^(-1)(0.65/1.3) = 26.56505118 degrees
90-26.56505118 = 63.43494882 degrees
Fq2M'x = -0.025533728(cos(63.43494882)) = -0.01141903
Fq3M'x = -0.01141903
FM',net = 2(-0.01141903) + 2(0.025533728) = 0.028229396N
Which is wrong of course. Where did I mess this up at?