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Fourier coefficient

  1. Nov 12, 2009 #1
    A periodic function f(x) has period 2 and is defined as

    f(x) = -2.4 (x+1) ,-1 ≤ x < 0
    2.4 (1-x) , 0 < x ≤ 1

    with f(x+2) = f(x) for all x

    sketch the graph of f(x) over the interval (-4, +4) and determine the Fourier coefficient Ao.

    I really don't know where to start with this question any help would be great.
     
    Last edited: Nov 12, 2009
  2. jcsd
  3. Nov 12, 2009 #2

    lanedance

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    hi longball, welcome to pf - where are you stuck? can you sketch the graph
     
  4. Nov 12, 2009 #3
    no i dont know where to start with the graph. Im guessing that the graph is to take the shape of a saw tooth, could be wrong though. i also do not understand what the (x+1) (x-1) stands for
     
  5. Nov 12, 2009 #4

    lanedance

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    start with the first part of the graph
    f(x) = -2.4 (x+1) ,-1 ≤ x < 0

    multiplying out the brackets gives
    f(x) = (-2.4)*x - 2.4
    this is the equation of a straight line, can you plot it on the x interval from -1 to 0?

    do similar for
    f(x) = (-2.4)*x + 2.4
    and plot it for on the x interval from 0 to 1
     
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