# Fourier Coefficients

1. Aug 1, 2007

### dimensionless

A function $$f(t)$$ can be represented by the expansion

$$f(t) = \frac{1}{2}A_{0} + A_{1}cos(\omega t) + A_{2}cos(2 \omega t) + A_{3}cos(3 \omega t) + .... B_{1}sin(\omega t) + B_{2}sin(2 \omega t) + B_{3}sin(3 \omega t) + ....$$

Do the constants $$A_{n}$$ and $$B_{n}$$ the same thing as the real and imaginary components of the Fourier transform? If so, why is there no imaginary component in the zeroth term?

2. Aug 1, 2007

### mathman

In computing the Fourier transform, the kernel is of the form einwt. For A0, the kernel is simply 1, so there is no imaginary part.