Fourier coefficients

  • Thread starter errordude
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  • #1
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Homework Statement


Hi i would just like some fast hints, i'm doing the integrals wrong, im splitting up the integral below and get the wrong answer.

well it's about finding the fourier series for f(t)={0 for -π<t<0 and sint for 0≤t≤π}

Homework Equations


[tex]a_{n} = \frac{1}{\pi}\int_{-\pi}^{\pi}f(t)\cos(nt) dt , n\in Z_{+}[/tex]


The Attempt at a Solution



well i split the integral up in finding [tex]a_{n}[/tex] like

[tex]\frac{1}{\pi}\int_{-\pi}^{\pi}f(t)\cos(nt) dt = \frac{1}{\pi}\int_{-\pi}^{0} 0· dt+\frac{1}{\pi}\int_{0}^{\pi}\sin(t)\cos(nt) dt[/tex]
Both of these elementary, but it fails to produce the right series.
Hints anyone?
 

Answers and Replies

  • #2
LCKurtz
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Did you forget the bn?
 
  • #3
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Did you forget the bn?

no but that just get to zero
 
  • #4
LCKurtz
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no but that just get to zero

They can't be zero because the function you are expanding is not an even function.
 
  • #5
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They can't be zero because the function you are expanding is not an odd function.

That's what i was thinking


[tex]
\frac{1}{\pi}\int_{-\pi}^{\pi}f(t)\sin(nt) dt = \frac{1}{\pi}\int_{-\pi}^{0} 0· dt+\frac{1}{\pi}\int_{0}^{\pi}\sin(t)\sin(nt) dt
[/tex]

but the above is zero!

i'm doing something wrong.
 
  • #6
LCKurtz
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I have to run now. You didn't show your work but I'm guessing you need to look what happens when n = 1.
 
  • #7
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halloo??

any1 who knows this fourier series

f(t)={0 for -π<t<0 and sint for 0≤t≤π}
 
  • #8
LCKurtz
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Nobody is going to just give you the answer. Show us your work for the an and bn and we will help you find the mistake.
 
  • #9
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Nobody is going to just give you the answer. Show us your work for the an and bn and we will help you find the mistake.

Hey man chill.

b_1=1/2 that was the problem.
 
  • #10
LCKurtz
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Hey man chill.

b_1=1/2 that was the problem.

Chill?? Surely you mean "Thanks for the suggestion, eh?"
 
  • #11
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Chill?? Surely you mean "Thanks for the suggestion, eh?"

you were right LC, b_1 was the crucial step.

thanx
 

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