Fourier coefficients

  • Thread starter errordude
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  • #1
errordude
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Homework Statement


Hi i would just like some fast hints, I'm doing the integrals wrong, I am splitting up the integral below and get the wrong answer.

well it's about finding the Fourier series for f(t)={0 for -π<t<0 and sint for 0≤t≤π}

Homework Equations


[tex]a_{n} = \frac{1}{\pi}\int_{-\pi}^{\pi}f(t)\cos(nt) dt , n\in Z_{+}[/tex]


The Attempt at a Solution



well i split the integral up in finding [tex]a_{n}[/tex] like

[tex]\frac{1}{\pi}\int_{-\pi}^{\pi}f(t)\cos(nt) dt = \frac{1}{\pi}\int_{-\pi}^{0} 0· dt+\frac{1}{\pi}\int_{0}^{\pi}\sin(t)\cos(nt) dt[/tex]
Both of these elementary, but it fails to produce the right series.
Hints anyone?
 

Answers and Replies

  • #2
LCKurtz
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Did you forget the bn?
 
  • #3
errordude
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Did you forget the bn?

no but that just get to zero
 
  • #4
LCKurtz
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no but that just get to zero

They can't be zero because the function you are expanding is not an even function.
 
  • #5
errordude
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They can't be zero because the function you are expanding is not an odd function.

That's what i was thinking


[tex]
\frac{1}{\pi}\int_{-\pi}^{\pi}f(t)\sin(nt) dt = \frac{1}{\pi}\int_{-\pi}^{0} 0· dt+\frac{1}{\pi}\int_{0}^{\pi}\sin(t)\sin(nt) dt
[/tex]

but the above is zero!

i'm doing something wrong.
 
  • #6
LCKurtz
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I have to run now. You didn't show your work but I'm guessing you need to look what happens when n = 1.
 
  • #7
errordude
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halloo??

any1 who knows this Fourier series

f(t)={0 for -π<t<0 and sint for 0≤t≤π}
 
  • #8
LCKurtz
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Nobody is going to just give you the answer. Show us your work for the an and bn and we will help you find the mistake.
 
  • #9
errordude
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Nobody is going to just give you the answer. Show us your work for the an and bn and we will help you find the mistake.

Hey man chill.

b_1=1/2 that was the problem.
 
  • #10
LCKurtz
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Hey man chill.

b_1=1/2 that was the problem.

Chill?? Surely you mean "Thanks for the suggestion, eh?"
 
  • #11
errordude
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Chill?? Surely you mean "Thanks for the suggestion, eh?"

you were right LC, b_1 was the crucial step.

thanx
 

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