Fourier of Half-Wave Rectified

  • Thread starter izen
  • Start date
  • Tags
    Fourier
In summary, the first term of the equation at k=1 has the form 0/0, resulting in the \frac{1}{2}x term. L'Hopital's Rule is then used to find the limit, which is equal to 1.
  • #1
izen
51
0

Homework Statement



half_wave.jpg


How did [itex]\frac{1}{2}x[/itex] come from at k=1?

Homework Equations

The Attempt at a Solution



because k=1 will make the first term at denominator 2(k-1) = [itex]\frac{0}{0}[/itex]
 
Physics news on Phys.org
  • #2
izen said:

Homework Statement



half_wave.jpg


How did [itex]\frac{1}{2}x[/itex] come from at k=1?

Homework Equations



The Attempt at a Solution



because k=1 will make the first term at denominator 2(k-1) = [itex]\frac{0}{0}[/itex]
Yes. The [itex]\ \frac{1}{2}x\ [/itex] comes from the fact that the first term has the form 0/0 as k → 1.

What is [itex]\displaystyle \ \lim_{t\to0}\frac{\sin(t)}{t}\ ?[/itex]
 
  • #3
SammyS said:
Yes. The [itex]\ \frac{1}{2}x\ [/itex] comes from the fact that the first term has the form 0/0 as k → 1.

What is [itex]\displaystyle \ \lim_{t\to0}\frac{\sin(t)}{t}\ ?[/itex]

Use L' Hopital's Rule --> [itex]\displaystyle \ \lim_{t\to0}cos(t) = 1 [/itex]

thank you SammyS
 

1. What is the Fourier transform of a half-wave rectified signal?

The Fourier transform of a half-wave rectified signal is a combination of the original signal's Fourier transform and its mirror image's Fourier transform. This is due to the fact that the rectification process introduces odd harmonics to the signal.

2. How does the amplitude of the Fourier transform of a half-wave rectified signal change with frequency?

The amplitude of the Fourier transform of a half-wave rectified signal decreases with increasing frequency. This is because the higher frequency components are filtered out by the rectification process, resulting in a decrease in amplitude for those frequencies.

3. Can a half-wave rectified signal have negative frequency components in its Fourier transform?

No, a half-wave rectified signal cannot have negative frequency components in its Fourier transform. This is because the rectification process only allows positive frequency components to pass through, resulting in a purely real Fourier transform.

4. What is the relationship between the Fourier transform of a half-wave rectified signal and its power spectral density?

The power spectral density of a half-wave rectified signal is equal to the square of its Fourier transform. This means that the power spectral density will have a similar shape as the Fourier transform, but with a different scale on the y-axis.

5. How does the Fourier series of a half-wave rectified signal differ from its Fourier transform?

The Fourier series of a half-wave rectified signal only contains odd harmonics, while the Fourier transform includes both odd and even harmonics. This is due to the fact that the Fourier series represents a periodic signal, while the Fourier transform represents a non-periodic signal.

Similar threads

  • Introductory Physics Homework Help
Replies
16
Views
386
  • Introductory Physics Homework Help
Replies
3
Views
360
  • Introductory Physics Homework Help
Replies
2
Views
222
  • Introductory Physics Homework Help
Replies
14
Views
335
  • Introductory Physics Homework Help
Replies
6
Views
218
  • Introductory Physics Homework Help
Replies
10
Views
897
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
11
Views
213
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Calculus and Beyond Homework Help
Replies
5
Views
321
Back
Top