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Homework Help
Calculus and Beyond Homework Help
Fourier series and differential equations
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[QUOTE="Pouyan, post: 5651692, member: 549817"] Well this is the whole solution from my book : If a has the form n[SUP]2[/SUP] + (-1[SUP]n[/SUP]) for some integer n≠0, then the problem has the solution y(t)= A*e[SUP]int[/SUP] + B*e[SUP]-int[/SUP] where A and B are constants. If a=1 there are the solutions y(t)=constant. For other values there are no nontrivial solutions. I know if a = n[SUP]2[/SUP] + (-1[SUP]n[/SUP]) then we can just enter this term into the equation and we have y''(t)+(n[SUP]2[/SUP] + (-1[SUP]n[/SUP]))y(t)=y(t+π) which has the solution y(t)= A*e[SUP]int[/SUP] + B*e[SUP]-int[/SUP] when n is not 0 or -1 or 1... but I don't know why... [/QUOTE]
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Calculus and Beyond Homework Help
Fourier series and differential equations
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