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sin n*(pi/2)

= 1 if n=1,5,9,13...

= -1 if n=3,7,11,15...

= 0 if n is even

cos n*(pi/2)

= 0 if n is odd

= -1 if n=0,4,8,12

= 1 if n=2,6,10,14...

is there a simpler way of expressing this?

for example simple way to express cos(n*pi)=cos(-n*pi)=(-1)^n

is there a similar way to express cos n*(pi/2) and sin n*(pi/2)

thanks

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# Homework Help: Fourier Series of n*(pi/2)

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