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Fourier Series of simple function.

  1. Oct 19, 2005 #1
    f(x) = cos(x) x from [-PI, 0]
    f(x) = -cos(x) x from ] 0, PI]

    I'm not sure how to deal with getting a fourier series for this function. (don't bother explaining theory, I know that, just can't apply it in this case) Could anyone help me out?
  2. jcsd
  3. Oct 19, 2005 #2
    okay, I think I got it!

    Ah well, what a stupid question that was. I figured it out.. now I just need to see what happens for even and odd harmonics and that'll be that. Thanks.
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