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Fourier series of Sin(2x)

  1. Sep 10, 2009 #1
    I have to find the fourier series of f(x)=sin(2x)
    but i always get all the coefficients (a0, an and bn) equal zero.
    is it right?
    Thank you
     
  2. jcsd
  3. Sep 10, 2009 #2

    lurflurf

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    It depends on what basis functions and interval you use. If the often used basis {1,cos(x),cos(2x),...,sin(x),sin(2x),...} with interval length 2pi the answer should be obvious.
     
  4. Sep 10, 2009 #3
    sin is an odd function, so half your coefficients should be zero, not all of them
     
  5. Sep 10, 2009 #4

    LCKurtz

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    Did you check b_2 carefully? It shouldn't be 0.
     
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