1. The problem statement, all variables and given/known data f(t) is an odd, periodic function with period 1 and: f(t) = -5.5 + 22*t2 for -0.5 ≤ t < 0 i) find the Fourier coefficient bn ii) find the Fourier coefficient b5 2. Relevant equations bn = (2/T) * ∫ f(t) *sin((2*n*∏*t)/T) dt between T/2 and -T/2 sin(n*∏) = 0 for all values of n cos(n*∏) = 1 for even values of n cos(n*∏) = -1 for odd values of n 3. The attempt at a solution by integrating f(t)*sin((2*n*∏*t)/T) with respect to t i get: -(11*sin(n*∏) - 11*n*∏*cos(n*∏))/(n^3 * ∏^3) replacing the sin(n*∏) with 0 i get: 11*cos(n*∏))/(n^2 * ∏^2) so this should be the solution to the first part of the question but when i put n into the equation as 5, i get the wrong answer. can anyone see where ive gone wrong?