What partCan you help me, please?
I think your b_{n}'s are correct except for b_{2}. I getIts hard to explain.
I did this exercise a lot of times, every time I get the same answer.
I can post the whole exercise to help me find what is wrong.
That Bn is kind hard to get right.
That formula doesn't work for n = 2 so you have to do b_{2} separately. Just directly work out the integralI got this:
Bn = (2*(-1)^n)/(2-n)^2 - (2*(-2)^n)/(2+n)^2
B2 = (2/(2-2)^2) - 1/8
What did you make to get that: (pi^2)/3
Thanks, finally I got the right answer.That formula doesn't work for n = 2 so you have to do b_{2} separately. Just directly work out the integral
[tex]\frac 2 \pi \int_0^\pi x^2 sin^2(2x)\, dx[/tex]