If a function belongs to G(R) but has points that are jump discontinuities, it's Fourier transform will not belong to G(R).(adsbygoogle = window.adsbygoogle || []).push({});

But would it be correct to claim that if a function in G(R) is continuous than its Fourier transform also belongs to G(R)? I guess it's not true, but can someone suggest a counterexample?

Thanks.

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# Homework Help: Fourier tranforms

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