1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Fourier tranforms

  1. May 8, 2008 #1
    If a function belongs to G(R) but has points that are jump discontinuities, it's Fourier transform will not belong to G(R).
    But would it be correct to claim that if a function in G(R) is continuous than its Fourier transform also belongs to G(R)? I guess it's not true, but can someone suggest a counterexample?
  2. jcsd
  3. May 8, 2008 #2


    User Avatar
    Staff Emeritus
    Science Advisor

    Frst, what do YOU mean by "G(R)"?
  4. May 8, 2008 #3
    Sorry, I wasn't sure whether this sign is well known.
    G(R) is the space of functions that might have points of discontinuity only of first kind, and which are absolutely integrable.
  5. May 8, 2008 #4
    ideas? anyone?...:frown:
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Fourier tranforms
  1. Laplace Tranforms (Replies: 1)

  2. Linear tranformations (Replies: 2)

  3. Laplace tranforms (Replies: 2)

  4. Linear Tranformations (Replies: 4)