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But would it be correct to claim that if a function in G(R) is continuous than its Fourier transform also belongs to G(R)? I guess it's not true, but can someone suggest a counterexample?

Thanks.

- Thread starter maria clara
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- #1

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But would it be correct to claim that if a function in G(R) is continuous than its Fourier transform also belongs to G(R)? I guess it's not true, but can someone suggest a counterexample?

Thanks.

- #2

HallsofIvy

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Frst, what do YOU mean by "G(R)"?

- #3

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G(R) is the space of functions that might have points of discontinuity only of first kind, and which are absolutely integrable.

- #4

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ideas? anyone?...

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