cant understand this transformation(adsbygoogle = window.adsbygoogle || []).push({});

i know that each derivative pops iw

and

[tex]\hat{y}' ->-ixy(x)[/tex]

[tex]\hat{y}'(\omega) ->-ixy(x)[/tex]

x is a signs of derivative

but i dont know how its been done in here

[tex]-ixy'(x)=(i\omega \hat{y}(w))'[/tex]

how they decided that is the derivative of this whole expression

muliplying by x means derivative

but here it something else

[tex]

f[xy'(\omega )]=i\frac{\mathrm{d} }{\mathrm{d} \omega}f[y'(x)]=i(i\omega \hat{y}(\omega))'=i(i \hat{y}(\omega)+i\omega \hat{y}'(\omega))[/tex]

i cant see what laws they follow here

?

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# Homework Help: Fourier transform question

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