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Fourier Transform

  1. Jul 4, 2011 #1
    Hey I am trying to figure out this easy problem, and I dont know if I am doing this properly or not heres the questions & the work.

    x(t) = ae^(bt)*u(-t)

    F[x(t)] = a*integral[(e^bt)*e^(-jwt)*dt] upper bound = 0 lower bound = -infinity
    = [a*e^(t(b-jw))] / (b-jw)
    = a/(b-jw)
  2. jcsd
  3. Jul 4, 2011 #2


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    Homework Helper

    What's u(-t), and why is it not part of the Fourier transform? Otherwise, your work is correct.
  4. Jul 4, 2011 #3
    u(-t) is the unit step function with a time reversal.
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