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## Homework Statement

Inverse fourier transform of X(w) = (sin(w/2).exp(-j2w))/(jw + 2)

## Homework Equations

From table:

exp(-bt).u(t) → 1/(jw+b)

multiplication by sin: x(t)sin(w

_{0}t → j/2[X(w+w

_{0})-X(w-w

_{0}]

w

_{0}being 0.5 here.

shifted left or right in time: x(t-c) → X(W)exp(-jwc)

## The Attempt at a Solution

I got x(t) = j/2[exp(-2(t-1.5)).u(t-1.5) - exp(-2(t-2.5).u(t-2.5)]

but I think it should be: x(t) = j/2[exp(-2(t-2.5).u(t-2.5) - exp(-2(t-1.5)).u(t-1.5)]

Any opinions?

Thanks