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## Homework Statement

Expand the fraction [tex]\frac{1}{\sqrt[n]{2^5}}[/tex], for [tex]n \in \mathbb{N}[/tex] and [tex]n \geq 2[/tex], to have denominator 2.

## Homework Equations

## The Attempt at a Solution

[tex]\frac{1}{\sqrt[n]{2^5}} \circ \frac{\sqrt[n]{{2}^{n-5}}}{\sqrt[n]{{2}^{n-5}}}[/tex]

[tex]\frac{\sqrt[n]{{2}^{n-5}}}{2}[/tex]

Is this correct?

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