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Fractional Equations

  1. Apr 3, 2005 #1
    Because I can't write squared, if x is squared, I will just write it like this: xsquared

    x/x +2 MINUS x/xsquared - 4 = x+3/x+2

    I get an LCD for each fracton and then I subtract getting this:

    xsquared - 2x MINUS x/xsquared - 4 = (x+3)(x-2)/xsquared - 4

    What do I do now?

    If you don't understand this just ask me to scan it
     
  2. jcsd
  3. Apr 3, 2005 #2
    I suppose you mean

    [tex] \frac{x}{x+2} - \frac{x}{x^2-4} = \frac{x+3}{x+2} \Longrightarrow \frac{x^2 - 3x}{x^2 - 4} = \frac{(x+3)(x-2)}{x^2 - 4}[/tex]

    which is fine.
     
    Last edited: Apr 3, 2005
  4. Apr 3, 2005 #3
    Or just learn LaTeX.

    I'm not quite sure what you mean. I surmise it is something like this:

    [tex]
    \frac{x}{x+2}-\frac{x}{x^2-4}=\frac{x+3}{x+2}[/tex]

    If it's not right, let me know.

    EDIT: Yarr, Data got there before I did...
     
  5. Apr 3, 2005 #4
    Moo, that was right what you posted

    And that is where I got but the instructions are to solve

    Is that a solution to it?
     
  6. Apr 3, 2005 #5
    Note that there is a small error in the thing you quoted, which I've corrected now.

    To solve, multiply [itex]x^2-4[/itex] through both sides, expand on the right, and see what you get.
     
  7. Apr 3, 2005 #6
    I don't want to learn Latex right now because it will take too long but I'll learn it for the future.

    This is what I'm getting:

    xsquared - 2x - x = xsquared + x - 6

    I subtract xsquared on each side to cancel them out getting:

    -2x - x = x - 6

    I then subract x from each side getting

    -3x - x = -6

    Then I subract the x

    -4x = -6

    Did I mess up?
     
  8. Apr 3, 2005 #7
    Looks right to me.
     
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