What is the correct equation for calculating free-electron density in sodium?

  • Thread starter hhhmortal
  • Start date
  • Tags
    Density
In summary, to find the free electron density of sodium, you need to calculate the total number of atoms in a unit cell, then use the atomic weight of sodium to determine the total number of electrons, and finally divide by the volume of the unit cell to get the free electron density. Alternatively, you can simply divide the number of free electrons (2) by the volume of the unit cell.
  • #1
hhhmortal
176
0

Homework Statement



The movovalent metal Na (sodium) has the body-centred cubic structure with a unit cell side length of 4.23 x 10^-10 m

What is the free electron density of sodium?

Homework Equations





The Attempt at a Solution



I used:

n = (6.02 x 10^23)(density of sodium) / (atomic mass) = 2.54 x 10^28 m^-3

But isn't this the number of atoms per unit volume not free electron density?


Thanks.
 
Physics news on Phys.org
  • #2
Its given that the structure is a BCC type unit cell. The total number of atoms present in a BCC are 2. You are given the dimensions of this unit cell. Since its a cubic cell, you can find the volume enclosed by it.

Each cell contains two atoms, how many cells do you need to get Na (Avagardo Number) atoms?

Once you have that, you know the atomic weight of Na sodium atoms. This weight is equal to the weight of the protons+neutrons+electrons. You know the weight of one electron. You know how many free electrons are present in one sodium atom (valency). Hence you know how many electrons are present in Na sodium atoms.

You also know the total volume enclosed by Na atoms (which you calculated in the beginning). So now you have the total number of free electrons present in a given volume, and can now find the free electron density.
 
  • #3
You can do it an a simpler way:
There are 2 free electrons per a volume of (4.23x10^-10)^3.
n=2/(4.23x10^-10)^3 =2.6x10^28
 
  • #4
chaoseverlasting said:
Its given that the structure is a BCC type unit cell. The total number of atoms present in a BCC are 2. You are given the dimensions of this unit cell. Since its a cubic cell, you can find the volume enclosed by it.

Each cell contains two atoms, how many cells do you need to get Na (Avagardo Number) atoms?

Once you have that, you know the atomic weight of Na sodium atoms. This weight is equal to the weight of the protons+neutrons+electrons. You know the weight of one electron. You know how many free electrons are present in one sodium atom (valency). Hence you know how many electrons are present in Na sodium atoms.

You also know the total volume enclosed by Na atoms (which you calculated in the beginning). So now you have the total number of free electrons present in a given volume, and can now find the free electron density.

Hi, I don't understand how I could get 'n' from this. I assumed that since its a monovalent metal it only has one valence electron therefore free electron density of sodium = density of sodium atoms. Hence I used the formula above to get the free electron density.
 
  • #5
you are right
 

1. What is free-electron density?

Free-electron density refers to the number of unbound or loosely bound electrons per unit volume of a material. It is a measure of the electron cloud present in a substance and is an important factor in determining its electrical and thermal properties.

2. How is free-electron density calculated?

The free-electron density can be calculated by dividing the total number of free electrons in a material by its volume. This can be determined using various techniques such as X-ray diffraction, electron microscopy, and spectroscopy.

3. What factors affect free-electron density?

The free-electron density in a material is influenced by several factors such as temperature, pressure, and the type of material. Metals tend to have a higher free-electron density compared to non-metals due to their structure and bonding properties.

4. Why is free-electron density important?

The free-electron density plays a crucial role in determining the electrical and thermal conductivity of a material. It also affects other properties such as magnetism and optical properties. Understanding and controlling the free-electron density is essential in designing and developing new materials with desired properties.

5. How does free-electron density relate to the band structure of a material?

The free-electron density is directly related to the band structure of a material. In metals, the electrons are delocalized and can move freely within the conduction band, resulting in a high free-electron density. In contrast, in insulators and semiconductors, the electrons are tightly bound to atoms and have limited movement, leading to a lower free-electron density.

Similar threads

  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
982
  • Introductory Physics Homework Help
Replies
8
Views
976
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
4K
  • Introductory Physics Homework Help
Replies
1
Views
4K
  • Introductory Physics Homework Help
Replies
7
Views
6K
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
2K
Back
Top