Free Electron Laser

  • Thread starter Raz91
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  • #1
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Homework Statement


i1k9vm.jpg



Homework Equations


2. (b)

I didn't understand how can I find the app. wavelength


The Attempt at a Solution



I tried : the electron move over λu with velocity β so the wavelength is λ≈λu
but its not the right answer.

my lecturer told me I should consider also the dopler

I only know that the answer is :
λ≈λu /(2*γ2)

γ= gamma
THANK YOU!
 

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Answers and Replies

  • #2
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I tried : the electron move over λu with velocity β so the wavelength is λ≈λu
This is the distance the light can travel while the electrons move by 1 structure length - but then the electrons moved forwards as well. What is the difference between those two distances?
 
  • #3
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the electron moves λu while the light moves λ≈λu /β
so the difference is λu [1/β-1]

so how can I use this fact to find the wave length?

I tried use the approximation β≈1-1q/(2*γ^2) for ultra-relativistic electrons
but still didnt get the right answer....


thank you
 
  • #4
35,437
11,862
1/β is also 1/(1+β-1) where β-1 is small, so you can express that fraction as ~1-β+1
That should lead to the right answer.
 

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