For the free expansion of an ideal gas into an evacuated chamber, I know that Work=0 and Q=0. Correct? This implies that the change in internal energy dU also equals 0. Since U depends solely on T, this should mean that the final temperature of the chamber is equal to the temperature of the ideal gas entering it. But what about the final pressure?(adsbygoogle = window.adsbygoogle || []).push({});

It's an ideal gas, so p1V1=RT1 and p2V2=RT2, but T1=T2, so p1V1=p2V2.

If you could point me in the right direction, that would be very helpful!

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# Free expansion of an ideal gas

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