A flowerpot falls off a windowsill and falls past the window below. You may ignore air resistance. It takes time 0.420 s to pass this window, which is of height 1.90 m.(adsbygoogle = window.adsbygoogle || []).push({});

Question- How far is the top of the window below the windowsill from which the flowerpot fell? Take the free fall acceleration to be 9.80m/s^2 .

given:

t = 0.420s

h = 1.90m

using the position formula

x(t) = x(0) + v(0)t + 1/2at^2

x(t) - x(0) = v(0)(0.42) - 4.9(0.42)^2

1.9 = v(0)(0.42) - 4.9(0.42)^2

v(0) = 6.59m/s

vf^2 - v(0)^2 = 2gh <--- now using this formula....

(6.582)^2 - 0 -2(-9.8)h

h = (6.582)^2/(9.8^2)

h = 2.21m

my answer is 2.21m, but it's wrong. i know im close, can someone help?

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# Homework Help: Free fall acceleration flowerpot problem

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