1.If i were to jump of of Mt. Everest (29,090 ft), how long will it take me to hit the ground? The initial velocity is 0, the pull of gravity is equal to 9.81m/s^2(acceleration). I got 42 seconds, but i didnt calculate terminal velocity so im pretty sure my answer is wrong to calculate time i used the equation t= the square root of twice the distance divided by the square root of the acceleration. I converted feet into meters by multiplying it by 30 cm/ft. from then on i just plugged the info in.