Free fall and newtons second law

  • #1

Homework Statement



A person jumps from the roof of a house 4.4 m high. When he strikes the ground below, he bends his knees so that his torso decelerates over an approximate distance of 0.70 m. The mass of his torso (excluding legs) is 40 kg.

(a) Find his velocity just before his feet strike the ground. ( I found as 9.2865)

(b) Find the average force exerted on his torso by his legs during deceleration. (I found as 2464 BUT THIS IS WRONG. I NEED YOUR HELP TO GET THIS. Thanks!)

Homework Equations





The Attempt at a Solution



(v final) ^2- (v initial)^2 = 2as
a = 9.8 m/s
s=4.4
v initial = 0
solve for v final
v final = 9.2865 m/s

same equation is used in reverse
v final = 0
v initial = 9.2865 m/s
s = 0.70 m this time
solve for a
a = 61.60 m/s

F = ma m is 40kg
F = 40*61.60 = 2464 newtons.
 

Answers and Replies

  • #2
954
117
2464 N is the net upward force exerted on his torso, not the force exerted on his torso by his legs - his torso still experiences a downward gravitational force.
 

Related Threads on Free fall and newtons second law

  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
8
Views
2K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
1
Views
3K
  • Last Post
Replies
1
Views
442
Replies
2
Views
11K
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
5
Views
3K
Top