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Free Fall Formula Question

  1. Oct 19, 2009 #1
    1. The problem statement, all variables and given/known data
    Figure out the height of the building using free fall formulas and only knowing two times: 3.25 second acceleration, 1.25 seconds decceleration. Find the height.

    2. Relevant equations
    Dy=V0t + 1/2at2 (only one I can think of that applies)

    3. The attempt at a solution

    Dy=V0t + 1/2at2

    Dy= 1/2at2

    Dy= .5(9.8m/s2)(10.5625)

    Dy= 51.8 m

    I am really stumped on this for some reason! I'm not even sure if I am using the correct formula. Any and all help is appreciated! Thanks y'all!!!
  2. jcsd
  3. Oct 20, 2009 #2


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    Welcome to PF!

    Hi PhunPhysicsss! Welcome to PF! :wink:
    Sorry, I've no idea what you mean. :redface:

    What's the full question? :smile:
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