Free fall physics expression

In summary, an object is released from rest and falls through the air with a resistive force of a = g - bv. The possible expression for the speed of the object as a function of time is v = gt - bt^2. For the second problem, the acceleration a of a particle with velocity v = at - bt^3 can be calculated by finding the maximum displacement in the positive x direction, which occurs when the velocity is 0.
  • #1
43
0
An object is releaseed from rest at time t = 0 and falls through the air, which exerts a resistive force such that the acceleration a of the object is given by a = g - bv, where v is the object's speed and b is a constant. If limiting cases for large and small values of t are considered, which of the following is a possible expression for the speed of the object as an explicit function of time?

a) v = g(1-e^bt) / b
b) v = (g+a)t / b
c) v = (ge^bt) / b
c) v = gt - bt^2
d) v = v_0 + gt, v_0 does not = 0

------------------------------------------------------------

The velocity of a particle moving along the x-axis is given by:

v = at - bt^3 for t > 0

a = 31m/s^2, b = 2.5 m/s^4, and t is in seconds.

What is the acceleration a, of the particle when it achieves its maxiumum displacement in the positive x direction? Answer in units of m/s^2.
 
Last edited:
Physics news on Phys.org
  • #2
For the first problem,the main thing you need to think about is "will the speed get greater or less? Which of the possible answer gives that?


For the second problem, as long as the velocity is positive, the particle is still moving forward. When the velocity is negative, it's already going to the left. The largest value of x 0ccurs when the veocity is 0.
 

Suggested for: Free fall physics expression

Replies
5
Views
547
Replies
14
Views
926
Replies
8
Views
946
Replies
15
Views
745
Replies
2
Views
675
Back
Top