# Free Fall

1. Jan 14, 2007

### ecthelion4

1. The problem statement, all variables and given/known data

A student standing on the ground throws a ball straight up. The ball leaves the studen'ts hand with a speed of 15 m/s when the hand is 2.0m above the ground. How long is the ball in the air before it hits the ground?

2. Relevant equations

I'm not sure

3. The attempt at a solution

Ok so I'm guessing I have to imply gravity will have an effect on the ball, i'm just not sure how it comes in the equation with the speed. and since there are no forces working on the x axis there should be no mention of range. I also checked on the hyper phisics site under free fall but the only relevant topic gives me this equation: Vy=Voy-gt, but that doesn't quite work for me since I can't clear it for t which is the variable I'm looking for. I need help.

2. Jan 14, 2007

You need an equation which will describe the position of the ball (i.e. the 'y coordinate') with respect to time.

3. Jan 14, 2007

### cristo

Staff Emeritus
You need to use the kinematic equations for motion with constant acceleration, which can be found http://www.glenbrook.k12.il.us/GBSSCI/PHYS/Class/1DKin/U1L6a.html [Broken] You know vi, a and d and want to find t, so pick a suitable equation.

edit: Damn, radou typed faster than me!

Last edited by a moderator: May 2, 2017
4. Jan 14, 2007

### ecthelion4

I guess I'd use this one:

d=Vi*t+1/2gt^2

It's the one that would work in my case since i got speed and g, but what do you say is d? is it the 2m the ball is apart from the x axis?

5. Jan 14, 2007

6. Jan 14, 2007

### ecthelion4

Oh I think I get it now

The equation is d=vi*t+1/2*a*t² , so if I substitute the values I know I get this:

2m=15m/s*t+1/2*9.8m/s²*t²

so now i just clear in terms of t right?

7. Jan 14, 2007