That is correct, you get a curve (what shape?) when plotting position vs. time for an object accelerating with constant acceleration. But this problem asks you to plot distance on the y-axis vs. t^2 on the x axis.J.live said:
A straight line on a distance vs time^2 graph represents a constant acceleration. It indicates that the object is moving with the same acceleration throughout its motion.
The slope of a straight line on a distance vs time^2 graph represents the acceleration of the object. The steeper the slope, the greater the acceleration.
The y-intercept of a straight line on a distance vs time^2 graph represents the initial velocity of the object. It indicates the velocity at the beginning of the motion.
Yes, the slope of a straight line on a distance vs time^2 graph can be negative. This would indicate that the object is decelerating, or slowing down, during its motion.
To calculate the acceleration of an object from a distance vs time^2 graph, you can use the formula a = 2d/t^2, where a is the acceleration, d is the distance, and t is the time. Simply plug in the values from the graph and solve for acceleration.
