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Free Falling Motion

  • #1

Homework Statement


An object is released from a height of 50m. How far has the object travelled during the 3rd second of fall?


Homework Equations


d = Vi*T + 1/2at^2

Doesn't work though - answer provided is 24.5m.


The Attempt at a Solution


I did a simple distance at 3 seconds with 9.81 m/s^2 as acceleration, got 29.43m. Using the formula above I got 44.45m - again, not 24.5m as provided for answer.


Thanks a lot!
 

Answers and Replies

  • #2
PhanthomJay
Science Advisor
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Homework Statement


An object is released from a height of 50m. How far has the object travelled during the 3rd second of fall?


Homework Equations


d = Vi*T + 1/2at^2

Doesn't work though - answer provided is 24.5m.


The Attempt at a Solution


I did a simple distance at 3 seconds with 9.81 m/s^2 as acceleration, got 29.43m.
you have calculated it's speed after 3 seconds, in m/s, not its distance.
Using the formula above I got 44.45m - again, not 24.5m as provided for answer.


Thanks a lot!
This formula is the correct one to use, but the problem is asking, somewhat vaguely, not for the distance traveled after 3 seconds, but rather, the distance traveled between the 2nd and 3rd second of travel.
 
  • #3
Got it.
Yep, wording was the only confusing part. Thanks a lot!
 

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