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Free Falling Motion

  1. Oct 22, 2008 #1
    1. The problem statement, all variables and given/known data
    An object is released from a height of 50m. How far has the object travelled during the 3rd second of fall?

    2. Relevant equations
    d = Vi*T + 1/2at^2

    Doesn't work though - answer provided is 24.5m.

    3. The attempt at a solution
    I did a simple distance at 3 seconds with 9.81 m/s^2 as acceleration, got 29.43m. Using the formula above I got 44.45m - again, not 24.5m as provided for answer.

    Thanks a lot!
  2. jcsd
  3. Oct 22, 2008 #2


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    Gold Member

    you have calculated it's speed after 3 seconds, in m/s, not its distance.
    This formula is the correct one to use, but the problem is asking, somewhat vaguely, not for the distance traveled after 3 seconds, but rather, the distance traveled between the 2nd and 3rd second of travel.
  4. Oct 22, 2008 #3
    Got it.
    Yep, wording was the only confusing part. Thanks a lot!
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