Free falling objects

  • Thread starter pberardi
  • Start date
  • Tags
    Falling
  • #1
16
0

Homework Statement



The height of a helicopter above the ground is given by h = 3.00t^2, where h is in meters and t is in seconds. After 2.00s the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground

Homework Equations


Xf = Xi + VxT + .5at^2


The Attempt at a Solution


h = 24
a = -9.8
Vi = 6.00t^2 at 2 = 24 m/s not sure about this

0 = 24 + 24t + .5(-9.8)t^2
t = 5.7

Did I go about this right? Please help.
 

Answers and Replies

  • #2

Homework Statement



The height of a helicopter above the ground is given by h = 3.00t^2, where h is in meters and t is in seconds. After 2.00s the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground

Homework Equations


Xf = Xi + VxT + .5at^2


The Attempt at a Solution


h = 24
a = -9.8
Vi = 6.00t^2 at 2 = 24 m/s not sure about this

0 = 24 + 24t + .5(-9.8)t^2
t = 5.7

Did I go about this right? Please help.

Wouldn't the initial height be 12? 2^2*3 = 12?

Also, do you do physics with calculus? If so, you could take the derivative of the height function to get the velocity function, and simply plug in for t. If not, you can only get the average velocity, which won't do you any good in this problem, since the helicopter is accelerating.
 
  • #3
I am sorry, my mistake. I did do the calculus. But I wrote the height function incorrectly. It is supposed to be h = 3t^3

So based on this new information, is it correct?
 
  • #4
I am sorry, my mistake. I did do the calculus. But I wrote the height function incorrectly. It is supposed to be h = 3t^3

So based on this new information, is it correct?
The initial height is correct, but the derivative of 3t^3 is 9t^2. With that in mind, the initial velocity would be 36.
 
  • #5
Should be
0 = 24 + 36t + .5(-9.8)t^2
t = 7.96
?
 
  • #6
Should be
0 = 24 + 36t + .5(-9.8)t^2
t = 7.96
?
That looks good.
 
  • #7
Thank you sir.
 
  • #8
They might deduct a couple points if units aren't shown in every step ...
0 = 24.0 m + (36.0 m/s) t + (1/2) (-9.8 m/s^2) t^2
 
Last edited:

Suggested for: Free falling objects

Replies
21
Views
207
Replies
6
Views
379
Replies
2
Views
429
Replies
1
Views
423
Replies
8
Views
450
Replies
7
Views
645
Replies
2
Views
458
Back
Top