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## Homework Statement

The height of a helicopter above the ground is given by h = 3.00t^2, where h is in meters and t is in seconds. After 2.00s the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground

## Homework Equations

Xf = Xi + VxT + .5at^2

## The Attempt at a Solution

h = 24

a = -9.8

Vi = 6.00t^2 at 2 = 24 m/s not sure about this

0 = 24 + 24t + .5(-9.8)t^2

t = 5.7

Did I go about this right? Please help.