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Homework Statement
The height of a helicopter above the ground is given by h = 3.00t^2, where h is in meters and t is in seconds. After 2.00s the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground
Homework Equations
Xf = Xi + VxT + .5at^2
The Attempt at a Solution
h = 24
a = -9.8
Vi = 6.00t^2 at 2 = 24 m/s not sure about this
0 = 24 + 24t + .5(-9.8)t^2
t = 5.7
Did I go about this right? Please help.