- #1

vabamyyr

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There is a post with lenght

I used energetic method and mvL= 0,5mv^2 plus or minus something.....

i have a feeling that it might be [tex] mgL= \frac 1 2 mv^2 - \frac 1 2 mgL \Longrightarrow v=\sqrt{3gL} [/tex]

but i dont know how to prove it? Can anyone help me?

**L**and it is being cut down from its lowest point. So the post starts a free fall with circular trajector. The question is that what is the**v**of upper part of post when it hits the ground?I used energetic method and mvL= 0,5mv^2 plus or minus something.....

i have a feeling that it might be [tex] mgL= \frac 1 2 mv^2 - \frac 1 2 mgL \Longrightarrow v=\sqrt{3gL} [/tex]

but i dont know how to prove it? Can anyone help me?

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