1MileCrash said:Your initial velocity is 0 m/s. The object is falling, but there is no reason to attribute a negative value to acceleration due to gravity on this coordinate system. It accelerates by 9.8 m/s every second.
v = 9.8(t)
1MileCrash said:If it is dropped from rest, it is falling towards earth. Acceleration is in that same direction, therefore the signs of velocity and acceleration must agree.
Freefall is the motion of an object under the influence of gravity, where the only force acting on the object is the force of gravity. Acceleration is the rate of change of an object's velocity, and in freefall, this acceleration is always equal to the acceleration due to gravity (9.8 m/s² near the Earth's surface).
The acceleration at 2 seconds refers to the acceleration of an object that has been falling for 2 seconds, while the acceleration at 10 seconds refers to the acceleration of an object that has been falling for 10 seconds. The two accelerations may be different because the object's velocity and position are constantly changing as it falls, affecting the acceleration.
The acceleration of an object at any given time in freefall can be calculated using the formula a = g - (v/t), where a is the acceleration, g is the acceleration due to gravity, v is the object's initial velocity, and t is the time in seconds.
In freefall, the acceleration remains constant throughout the entire motion, regardless of the time. This means that the acceleration at 2 seconds, 10 seconds, or any other time will always be the same. This is because the force of gravity is always acting on the object, causing it to accelerate at a constant rate.
In real-world scenarios, air resistance or drag can affect an object's motion in freefall. As an object falls, it experiences a force of air resistance in the opposite direction of its motion, which increases as the object's velocity increases. This can cause a decrease in acceleration and a decrease in the object's overall speed.