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Freely falling body!

  • Thread starter ritwik06
  • Start date
  • #1
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1.For a freely falling body under gravity:
1.Why does the slope of S vs. t^2 gives g/2? Why not g itself????
2.Does the graph exhibit linear relationship?

I have studied that the slope of a velocity time graphy gives the acceleration directly. Now when we make a graph for S vs. t^2 from a graph of velocity-time for a freely falling body. So why does the slope of the graph obtained gives g/2?
 

Answers and Replies

  • #2
cristo
Staff Emeritus
Science Advisor
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Think of the equation relating position and acceleration (kinematic equation) for a particle with zero initial velocity
 
  • #3
580
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Think of the equation relating position and acceleration (kinematic equation) for a particle with zero initial velocity
s=0.5*gt^2

right??
 
  • #4
580
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I got it!! Thanks!
 

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