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Freely falling body!

  1. Feb 2, 2007 #1
    1.For a freely falling body under gravity:
    1.Why does the slope of S vs. t^2 gives g/2? Why not g itself????
    2.Does the graph exhibit linear relationship?

    I have studied that the slope of a velocity time graphy gives the acceleration directly. Now when we make a graph for S vs. t^2 from a graph of velocity-time for a freely falling body. So why does the slope of the graph obtained gives g/2?
  2. jcsd
  3. Feb 2, 2007 #2


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    Think of the equation relating position and acceleration (kinematic equation) for a particle with zero initial velocity
  4. Feb 3, 2007 #3

  5. Feb 3, 2007 #4
    I got it!! Thanks!
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