- #1

cala

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**freely maintained water transference**

Hello again.

Just a little and simple question, i think you'll see what i mean:

Imagine a full tank of water 1m long. This tank has a spring behind, compressed by the water weight on top. This spring is 1m long from the ground, so the water is at 2m from the ground.

Imagine another empty tank of the same dimensions. This tank has another spring behind, but as the tank has no water, the spring is uncompressed. This uncompressed spring is 2m long from the ground, so the tank is at 2m from the ground.

The two tanks are connected, but as the water level on one tank is the same as the ground on the other, no transference happen.

Now, you compress a part of the uncompressed spring, say 0.2m from the ground to 0.1m. This effect is the same that a water level of 0.1m will cause.

Now, the ground of the empty tank is 0.1m behind the water level of the full tank (because you compressed the spring, but not with water weight), so a water transfer starts.

the sequence now happens like this:

A-water...A-spring...A-total...B-water...B-spring...B-total

1m...1m...2m...0m...2m...2m

1m...1m...2m...0m...1.9m...1.9m

0.9m...1.1m...2m...0.1m...1.8m...1.9m

0.8m...1.2m...2m...0.2m...1.7m...1.9m

. . . . . .

. . . . . .

0.2...1.8m...2m...0.8m...1.1m...1.9m

0.1m...1.9m...2m...0.9m...1m...1.9m

0m...2m...2m...1m...1m...2m

As you can see, we apply the force of 0.1m of water weight to the spring to start the process , and obtain 10 times (1m) the transference of this water.

If the tanks were 50 times longer (5m) than the equivalent water energy input (and supposing the springs could follow the same changes), then we will get 50 times the transference of the initial equivalent water.

I mean, you can apply the same work to start, and have a longer or shorter transference between the tanks, independent of the initial energy input. The transference depends of the kind of tanks and springs.

So, as energy input is independent of the process, what avoid us to get more energy from the process than the needed to start it again to the other hand?.

For example, a turbine connecting behind the tanks will collect the energy from the transference, and later we could use this energy to compress a part of the spring to start the process again.

Of course, the turbine will oppose to the transference in some manner, but if the initial level difference of the water tanks is big enough, this opposition can be bypassed, and start the process.

At this point, the energy input needed is only to pass the turbine opposition. Once the turbine start to work, the transfer is maintained at the same water levels, and this transference could be for a long time, obtaining several times the energy needed to start it.

Any question?

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