A violin string has a length of 0.350 m and is tuned to concert G, with fG = 392 Hz. Where must the violinist place her finger to play concert A, with fA = 420 Hz? If this position is to remain correct to half the width of a finger (that is, to within 0.600 cm), what is the maximum allowable percentage change in the string tension? Ok so I already figured out the first question, the position to play concert A is 32.6666... cm from the bridge. I obtained this answer from dividing the equations, canceling, and solving. It is the algebra of the second part that is giving me trouble, and I am not sure how to approach it. I am sure it too has to be done by dividing two equations for the frequencies and ending up with with a ratio of the two tensions. I just can't seem to get it. I really need the answer by 5:00PM Central time, don't know if anyone will be able to solve it, but I'd appreciate any help.