AdrianHudson said:Homework Statement
Consider a mass hanging from an ideal spring. Assume the mass is equal to 1 kg and the spring constant is 10 N/m. What is the characteristic frequency of this simple harmonic oscillator?
Homework Equations
No idea I think Hookes law
F=-ky
Some other relevant equations?
[itex]\omega^{2}[/itex] = K/M
The Attempt at a Solution
No idea where to start. Some guidance on steps would be helpful! thanks
A simple harmonic oscillator is a system or object that moves back and forth between two points in a regular and predictable manner. It follows the principles of harmonic motion, where the force acting on the object is directly proportional to its displacement from its equilibrium position.
The frequency of a simple harmonic oscillator is calculated using the equation f = 1/(2π√(k/m)), where f is the frequency in hertz (Hz), k is the spring constant of the oscillator, and m is the mass of the object attached to the spring.
The frequency of a simple harmonic oscillator is affected by the mass of the object attached to the spring, the spring constant of the oscillator, and the amplitude of the oscillation. It is also influenced by external factors such as friction and air resistance.
As the mass of the object attached to the spring increases, the frequency of the simple harmonic oscillator decreases. This is because a heavier object requires a greater force to achieve the same amplitude of oscillation, resulting in a lower frequency.
Yes, the frequency of a simple harmonic oscillator can be changed by altering its mass, spring constant, or amplitude of oscillation. External factors such as friction and air resistance can also affect the frequency. Additionally, changing the length of the spring or the gravitational pull can also impact the frequency of the oscillator.