There's a horizontal thin wire whose mass is negligible and whose length is l=1m. It is strained with constant force F=10N. If we place a tiny pellet in the middle of wire (mass of pellet is m=1g) and then we bring wire out of equilibrium position (moving out of it's original position is normal to the wire, 90 degrees). Determine the frequency of oscillation of wire.
The Attempt at a Solution
We know that, since this is oscillation motion, following equation holds:
x'' + ω^2 x=0 ,where x is amplitude, so we could actually try to find acceleration (a=x'') in function of amplitude x, and then, expression multiplied by x would be ω^2 and then, since ω=2πf we could easily find f here, but i don't know how to determine x''. Any ideas?