A person pushes a 14kg lawn mover at constant sped with a force of 88N directed along the handle, which is at an angle of 45 degress to the horizontal. (a) draw the Free-body diagram showing all forces acting on the mower. (b) Calculate the horizontal friction force on the mower, then (c) the normal force exerted vertically upward on the mower by the ground. (d) What force must the person exert on the lawn mower accelerate it from rest to 1.5m/s in 2.5 seconds, assuming the same friction force?
Fgx= Fg sin Theta
Are those correct??
The Attempt at a Solution
The best I can figure is that each equals the same but im not sure what the frictional force is. Is it Fgy or Fgx im just not sure on much.