1. The problem statement, all variables and given/known data The coefficient of static friction is 0.673 between the two blocks shown. The coefficient of kinetic friction between the lower block and the floor is 0.113. Force F causes both blocks to cross a distance of 7.20m, starting from rest. What is the least amount of time in which the motion can be completed without the top block sliding on the lower block, if the mass of the lower block is 1.90kg and the mass of the upper block is 2.54kg? 2. Relevant equations Force Friction = μ*Force Normal Δd= vt +0.5aΔt2 3. The attempt at a solution From what I know is that the force static friction is the total amount of force allowed without allowing it to slip. Force Friction = μ*Force Normal Force Friction = 0.673*(mass of top block*gravity) Force Friction = 0.673*(2.54*9.8) Force Friction = 16.75 N Now F=ma 16.75/(mass of top+bottom)=a 16.75/4.44=a 3.77 m/s^2 = a Now Δd= vt +0.5aΔt2 7.2= 0*t +0.5(3.77)Δt2 Solve for t....1.95 seconds.....wrong.... What Am I doing wrong?