(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Sam, whose mass is 67 kg, takes off across level snow on his jet-powered skis. The skis have a thrust of 230 N and a coefficient of kinetic friction on snow of 0.13. Unfortunately, the skis run out of fuel after only 12.

2. Relevant equations

F-Fk=mA

(Vx)f = (Vx)i + (Ax)(Delta Time)

Xf=Xi+((Vx)i)(delta Time) + .5(Ax)(Delta Time)^2

3. The attempt at a solution

Well I first started out by find the acceleration:

230-(.13)(67)(9.8)=67Ax

Ax=2.15

So I plugged that into the equation to find the max speed...

(Vx)f= 2.15 x 12 = 25.8 m/s rounded to 2 sig figures 26 m/s

According to mastering physics Im correct up to here. Finding the distance traveled is where Im getting the answer incorrect.

I tried using the equation Xf=Xi+((Vx)i)(delta Time) + .5(Ax)(Delta Time)^2

Xf= 0 + (26)(12) + .5(2.15)(12)^2 = 466.8 M

Mastering physics ask for it to be rounded to 2 sig figures giving 470 m. But yet that answer is incorrect. What am I doing wrong? If somebody can help me I'd appreciate it. Thanks!

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# Homework Help: Friction and distance traveled

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