# Friction and Energy Conversion

## Homework Statement

A 1100kg car is traveling at 24m/s before it hits a 18m patch of mud with a 1.7 x 10^4 net horizontal resistive force. What is the cars speed as it leaves the mud patch?

## Homework Equations

Change in Uint= fd
KE= 1/2mv^2
W= Fd

## The Attempt at a Solution

1/2mv^2 = f(mud on car)d
1/2(1100)v^2 = 1.7 x 10^4(18)
V= 23.6 m/s

I'm pretty sure this isn't correct, because the resistive force is too great to have the final velocity change only slightly. I feel like I might need to incorporate work or the initial velocity into my equation, but I don't really know how.

gneill
Mentor

## Homework Statement

A 1100kg car is traveling at 24m/s before it hits a 18m patch of mud with a 1.7 x 10^4 net horizontal resistive force. What is the cars speed as it leaves the mud patch?

## Homework Equations

Change in Uint= fd
KE= 1/2mv^2
W= Fd

## The Attempt at a Solution

1/2mv^2 = f(mud on car)d
1/2(1100)v^2 = 1.7 x 10^4(18)
V= 23.6 m/s

I'm pretty sure this isn't correct, because the resistive force is too great to have the final velocity change only slightly. I feel like I might need to incorporate work or the initial velocity into my equation, but I don't really know how.

The car starts out with some initial KE due to its initial velocity. The friction "robs" energy from this initial store of KE. So find out how much KE is left after traversing the mud patch...

BvU