a) Find the net forces acting on the puck. Remember to consider both horizontal and vertical forces.
b) If the puck leaves the stick with a velocity of 45m/s, how far will the puck travel in 3 seconds?
Fnet (horizontal) = fapplied + forced friction
Fnet (vertical) = f gravity + f normal
Δd = (horizontal distance traveled) x (change in time)
c^2 = a^2 +b^2
f = (mass) x (acceleration)
The Attempt at a Solution
For a, I start with finding the horizontal net force by using the first equation. After adding both the frictional force and applied force, I yield 16.05 N. Then I find the force of gravity by using the last equation (0.164 kg)(9.8m/s^2) and yields a value of 1.568 N. I know the magnitude of the force of gravity is equal to force normal, so that would also be 1.568 N. Now I use the second equation to find the vertical net force, which yields 3.136 N. Now that the net-forces are perpendicular, I use pythagorean theorem to find the resultant which yields 16.4 (√(3.316N)^2 + (16.05 N)^2) and finally yielded a value of 16.4 N as the total net force that is acting on the puck. Is this correct? I may have wrongly assumed that, there is a vertical net force due to the question asking to consider both vertical and horizontal forces and I haven't solved a question with a vertical net force in the lesson as of yet.
For b, I actually have no idea how to solve, seeing as I haven't even seen a question like this in the lesson nor are there any examples. I assume we use the third equation which would then yield a value 135 m.
Thanks in advance.