# Friction and forces?

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1. Jan 20, 2015

### thegoosegirl42

1. The problem statement, all variables and given/known data
A box of Cheerios and a box of Wheaties are accelerated across a horizontal surface by a horizontal force F applied to the Cheerios box. The magnitude of the frictional force on the Cheerios box is 2N, and the magnitude of the frictional force on the Wheaties box is 4N. If the magnitude of F is 12N, what is the magnitude of the force on the Wheaties box from the Cheerios box.

2. Relevant equations
Friction=uN
F=ma

3. The attempt at a solution
a=F/m
12-2-4=6
a=6/(C+W) ----- I am using C and W to represent the mass of the different boxes.
Cgu=2
Wgu=4
However I don't know where to use substitution on this.

2. Jan 20, 2015

### Staff: Mentor

If the coefficient of kinetic friction is the same for both boxes, how does the mass of the cheerios box compare with the mass of the wheaties box? Once you know this, draw a free body diagram of the wheaties box, and write down the force balance equation for the wheaties box.

Chet

3. Jan 20, 2015

### thegoosegirl42

I didn't think that the frictional forces were equal but if they are the mass of the bigger one is twice that of the smaller one.

4. Jan 20, 2015

### Staff: Mentor

The equations you wrote in post #1 imply that you do think the coefficients of friction are equal.

Let's see the force balance from your free body diagram of the wheaties box.

Chet

5. Jan 21, 2015

### CWatters

Chet said "coefficient of kinetic friction" not "frictional forces". There is a difference.

6. Jan 21, 2015

### thegoosegirl42

Yeah, I meant coefficient of friction but I didn't realize until I replied and by then it was too late. :-(

7. Jan 21, 2015

### thegoosegirl42

Thank you so much. I guess I was just reading too far into the problem.