I'm trying to work out a problem involving the stopping distance of a skiier, and I thought it was a straightforward problem but I've gone wrong somewhere.(adsbygoogle = window.adsbygoogle || []).push({});

Determine the stopping distance for a skier moving down a slope with friction with an initial speed of 22.2 m/s.

Assume μk=0.173 and θ=4.9

To solve, I tried the formula:

Xinitial= Vsquared/2g(sinθ + μkcosθ)

so i used the data given and got

X=(22.2)squared/2(9.8)(sin4.9+0.173cos4.9)

= 97.5 m

but this did not work out.

Anyone have any thoughts?

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# Homework Help: Friction and stopping distance

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