# Friction between table and pool ball

1. Dec 9, 2004

### Drey0287

Assume the weight of a pool ball is .17kg. If the ball traveled 1.2 m in 5.3 seconds, what is the force of Friction and coefficient of friction between the pool ball and the table?

Now, All I know how to do it calculate the normal force which is (9.8)(.17) = .1666 but where do i get from here???

2. Dec 9, 2004

### dextercioby

Hints:Use Newton's second law for the rotational motion.(torque is the sum of momenta of all forces).From there u should find µ.The normal force u calculated should be ten times bigger.
$$I=\frac{3mr^{2}}{5}$$

Daniel.

3. Dec 9, 2004

### soccerjayl

I find the acceleration to be 0.04272 m/s^2

Therefore, can you not find the force of friction through F=ma?

F(subF)=(.17kg)(0.04272 m/s^2)

mew=F(subF)/F(subN)

mew=0.007262/0.1666

mew=0.0436

check my work, i may be wrong

4. Dec 9, 2004

### dextercioby

My µ approximately equal to 0,003.

Show your reasoning to depict you mistakes.

Daniel.