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Homework Help: Friction between table and pool ball

  1. Dec 9, 2004 #1
    Assume the weight of a pool ball is .17kg. If the ball traveled 1.2 m in 5.3 seconds, what is the force of Friction and coefficient of friction between the pool ball and the table?

    Now, All I know how to do it calculate the normal force which is (9.8)(.17) = .1666 but where do i get from here???
     
  2. jcsd
  3. Dec 9, 2004 #2

    dextercioby

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    Hints:Use Newton's second law for the rotational motion.(torque is the sum of momenta of all forces).From there u should find µ.The normal force u calculated should be ten times bigger.
    [tex] I=\frac{3mr^{2}}{5} [/tex]

    Daniel.
     
  4. Dec 9, 2004 #3
    I find the acceleration to be 0.04272 m/s^2

    Therefore, can you not find the force of friction through F=ma?

    F(subF)=(.17kg)(0.04272 m/s^2)

    mew=F(subF)/F(subN)

    mew=0.007262/0.1666

    mew=0.0436

    check my work, i may be wrong
     
  5. Dec 9, 2004 #4

    dextercioby

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    My µ approximately equal to 0,003.

    Show your reasoning to depict you mistakes.

    Daniel.
     
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