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Masses m1 and m2 rest on a table 1.2 meters above the floor and are attached to m3 via a very light string and a frictionless pulley as shown above. The coefficient of static friction between the m2 and the table is μs = 0.21 and their coefficient of kinetic friction is μk = 0.14. m2 = 56 kg and m3 = 28 kg.
a) What is the minimum mass that m1 can have to keep the two blocks from sliding off the table?
b) m1 is completely removed. What will be the acceleration of m3? (assume up to be the positive direction).
The Attempt at a Solution
I havn't gotten to b yet only attempted a so far.
a) i make the free body diagram and end up with the following equations.
for m1 [tex]\Sigma[/tex] Fy = N1-m1*g=0
for m2 [tex]\Sigma[/tex] Fy= N2-N1-m2*g=0
and [tex]\Sigma[/tex] Fx= T-[tex]\mu[/tex]s*N2=0
and for m3 [tex]\Sigma[/tex] Fy= T-m3*g=0
From there i solve the m3 for T then m2 Fx for N2 then Fy2 for N1 and finally the first for m1. But that doesnt work at all. So if anyone can point out what goes wrong id be glad to hear it.
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