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**1. The problem statement, all variables and given/known data**

Two cars are going to begin at rest and race 200 meters to a stoplight. One driver sneaks over and puts oil on the other car's tires, which reduces it coefficient of friction to .07. Assuming the first car does not slip then by how much distance will it win?

**2. Relevant equations**

Ff = μ(Fn)

a = μ(9.8)

Vf^2 = Vi^2 + 2a * x

Static coefficient of friction of rubber on concrete = 1.0

Kinetic coeff. of friction of rubber on concrete = 0.8

**3. The attempt at a solution**

1st car:

Vf^2 = 2(.8*9.8)200

vf = 39.6 m/s

2nd car:

a = .07(9.8)

a = .686 m/s^2

vf^2 = 2(.686)

vf = 1.2 m/s

Not sure what to do now.